Question

Container A and container B have leaks. Container A has 800 mL of water, and is leaking 6mL per minute. Container B has 1000 mL, and is leaking 10mL per minute. How many minutes, m, will it take for the two containers to have the same amount of water?

Answer 1

x = 50 minutes

Explanation:

GIven:

Container A contain = 800 mL

Container B contain = 1,000 mL

Container A leak = 6 mL per min

Container B leak = 10 mL per min

Computation:

Assume; in x minute

So,

800 - 6x = 1,000 - 10x

4x = 200

x = 50 minutes