Answer:
Var(x)=1
Explanation:
x p(x) x² x*p(x) x²*p(x)
0 1/4 0 0 0
1 1/8 1 1/8 1/8
2 1/2 4 1 2
3 1/8 9 3/8 9/8
Total 3/2 13/4
The required variance can be computed as
Var(x)=sumx²*p(x)-(sum(x*p(x)))²
Var(x)=13/4-(3/2)²
Var(x)=13/4-9/4
Var(x)=4/4
Var(x)=1
Thus, the required variance is 1.