Question

What is the ph of a 0.00043 molar solution of lithium hydroxide (lioh)?

Answer 1

pH = 10.63.

Step-by-step explanation:

Recall that lithium hydroxide (LiOH) is a strong base and hence dissociates completely into Li⁺ and OH⁻ ions.

Therefore, the concentration of OH⁻ ions is equivalent to the concentration of the base.

Find pOH:

`\displaystyle \begin{aligned} \text{pOH} & = -\log[\text{OH}^-] \\ \\ & = -\log(0.00043) \\ \\ & = 3.37 \end{aligned}`

Using the relationships between pH and pOH, hence determine pH:

`\displaystyle \begin{aligned}\text{pH} + \text{pOH} & = \text{p}K_w = 14.00 \\ \\ \text{pH} & = 14.00 - 3.37 \\ \\ & = 10.63\end{aligned}`

In conclusion, the pH of the solution is about 10.63.