Question

A type of elevator called a cage is used to raise and lower miners in a mine

shaft. Suppose the cage carries a group of miners down the shaft. If the
unbalanced force on the cage is 60.0 N, and the mass of the loaded cage is
1.50 x 10²kg, what is the acceleration of the cage?

Answer 1

Acceleration, a = 0.04 m/s²

Step-by-step explanation:

Given the following data;

Force = 60N

Mass = 1500kg

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

`F = ma`

Where;

F represents force.

m represents the mass of an object.

a represents acceleration.

Making acceleration (a) the subject, we have;

`Acceleration (a) = (F)/(m)`

Substituting into the equation;

`Acceleration (a) = (60)/(1500)`

Acceleration, a = 0.04 m/s²