Question

(a) Suppose that a person has an average heart rate of 72.0 beats/min. How many beats does he or she have in 2.0 y

Answer 1

`7.56* 10^7\ \text{beats}`

Explanation:

It is given that,

A person has an average heart rate of 72.0 beats/min.

We need to find how many beats does he or she have in 2.0 years, t = 2 Y

Converting years to min.

`t=2\text{year}* \frac{365\ \text{days}}{\text{year}}* 24\frac{h}{\text{day}}* \frac{60\text{min}}{\text{hour}}\\\\t=1051200\ \text{min}`

So, no of beats in 2 years is given by :

`b=72\ \text{beats/min}* 1051200\ \text{min}\\\\b=7.56* 10^7\ \text{beats}`

Hence, the required answer is
`7.56* 10^7\ \text{beats}`.