Answer:
(a) the angle between the wire and field is 30⁰
(b) the force is 4.8 N
Step-by-step explanation:
Given;
current in the wire, I = 8 A
magnetic field, B = 1.2 T
length of the wire, L = 50.0 cm = 0.5 m
magnetic force, F = 2.4 N
The magnetic force on the wire is given by;
F = BILsinθ
where;
θ is the angle between the wire and field
sinθ = F / BIL
sinθ = 2.4 / (1.2 x 8 x 0.5)
sinθ = 0.5
θ = sin ⁻¹ (0.5)
θ = 30⁰
(b) the force on the wire if it is rotated to make an angle of 90⁰
F = BIL(sin90⁰)
F = BIL(1)
F = BIL
F = 1.2 x 8 x 0.5
F = 4.8 N