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How fast would a 4.75 cm copper bar have to move at right angles to a 0.700 T magnetic field to generate 1.50 V (the same as a AA battery) across its ends
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How fast would a 4.75 cm copper bar have to move at right angles to a 0.700 T magnetic field to generate 1.50 V (the same as a AA battery) across its ends

User Twopheek
by
5.5k points

1 Answer

5 votes

Answer:

ω = 1899.5 radian / s

Step-by-step explanation:

EMF induced by a rotating rod = 1 /2 B ω L² where ω is angular velocity of rod and L is its length . B is magnetic field

1 /2 B ω L² = 1.5

1/2 x .7 x ω x .0475² = 1.5

ω = 1899.5 radian / s

User Viktorzeid
by
5.7k points
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