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What is the area of the rectangle with the dimensions of 2x+6 and x-2

1 Answer

1 vote

Answer:

2x^2+2x−12 or (2x+6)*(x-2)

Explanation:

Area: (2x+6)*(x-2)

now, we simplify.

(2x+6)*(x-2)=(2x+6)(x+(−2))

=(2x)(x)+(2x)(−2)+(6)(x)+(6)(−2)

=2x^2−4x+6x−12

=2x^2+2x−12

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