Question

`8x^2 +y^2=10`
find dy/dx

Answer 1

See Explanation

Step-by-step explanation:

`8 {x}^(2) + {y}^(2) = 10 \\ \\ {y}^(2) = 10 - 8 {x}^(2) \\ \\ differentiating \: w \: r \: t \: x \: on \: both \: sides \\ \\ 2y (dy)/(dx) = (d)/(dx) (10 - 8 {x}^(2) ) \\ \\ 2y (dy)/(dx) = 0 - 8 * 2 {x} \\ \\ 2y (dy)/(dx) = - 16{x} \\ \\ (dy)/(dx) = ( - 16x)/(2y) \\ \\ (dy)/(dx) = - (8x)/(y)`