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The area of rectangle is 120 m² and its breadth is 8 m. Find the perimeter of the rectangle.​

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Given:

• Area of rectangle = 120 m²

• Breadth = 8m

To find :

• perimeter of the rectangle .

Solution:

As we know that ,

• Area of rectangle = L× B

=> 120 = L × 8

=> L = 120/8

=> L = 15

Length of the rectangle is 15m .

Now ,

• perimeter of rectangle = 2 (L+B)

=> perimeter of rectangle = 2 (15+8)

=> perimeter of rectangle = 2 ( 23)

=> perimeter of rectangle = 46

Hence, the perimeter is 46 m .

I hope it will help you.

Regards.

User Nhjk
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