Given:
• 2k -1 , 7 and 11 are in AP .
To find :
• The value of k .
Solution :
• As we know that , In AP common difference is same .
• b - a = c - b
=> 2b = a + c
Here :
• a = 2k-1
• b = 7
• c = 11
=> 2 (7) = 2k-1+11
=> 14 = 2k+10
=> 2k = 14-10
=> 2k = 4
=> k = 4/2
=> k = 2 .
Hence ,the value of k is 2 .
Hope it will help you.
Regards.