Question

Please help, this has to do with kinematic equations

A body moving with uniform acceleration has a velocity of 15.9 cm/s when its x coordinate is 4.26 cm.
If its x coordinate 2.62 s later is −3.18 cm, what is the x-component of its acceleration?
Answer in units of cm/s²

Answer 1

`a=-14.3\ cm/s^2`

Step-by-step explanation:

Given that,

Initial velocity of a body, u = 15.9 m/s

Initial position,
`x_i=4.26\ cm=0.0426\ m`

Final position,
`x_f=-3.18\ cm=-0.0318\ m`

Time, t = 2.62 s

We need to find the x-component of its acceleration. using second equation of motion to find it as follows :

`x_f-x_i=ut+(1)/(2)at^2`

Putting all the values to find a.

`-3.18-4.26=15.9(2.62)+(1)/(2)a(2.62)^2\\\\-49.098=3.4322a\\\\a=-14.3\ cm/s^2`

So, the acceleration of a body is
`-14.3\ cm/s^2`.