Question

a robotic vacuum is at rest at its charging station. it leaves to clean the house accelerating to 0.3.meters per second in 0.8 seconds. whats is the magnitude of the vacuums acceleration

Answer 1

Acceleration, a = 0.375 m/s²

Step-by-step explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

`Acceleration (a) = (final \; velocity - initial \; velocity)/(time)`

`a = (v - u)/(t)`

Where,

• a is acceleration measured in
  `ms^(-2)`

• v and u is final and initial velocity respectively, measured in
  `ms^(-1)`

• t is time measured in seconds.

Given the following data;

Initial velocity, u = 0m/s

Final velocity, v = 0.3m/s

Time, t = 0.8secs

Substituting into the equation, we have;

`a = (0.3 - 0)/(0.8)`

`a = (0.3)/(0.8)`

Acceleration, a = 0.375 m/s²

Therefore, the the magnitude of the vacuum's acceleration is 0.375 m/s²