Question

What are the roots of the equation x² + 6x-9 = 07

Answer 1

x1 =-3+3
`√(2)` and x2=-3-3
`√(2\\)`

Explanation:

x² + 6x-9 = 0

-6±
`\sqrt{6^(2)-4(1)(-9) }` / 2

-6±
`√(72)` /2

so

x1 = -6+
`\sqrt{72` /2

x1 =-3+3
`√(2)`

and

x2 = -6-
`\sqrt{72` /2

x2=-3-3
`√(2\\)`