Answer:
The standard deviation of the sample mean
![\mathbf{\sigma _x =0.1049}](https://img.qammunity.org/2021/formulas/mathematics/college/aey5a9se39e8p8rjxwh13rmpjilgkhf0wl.png)
Explanation:
We are provided with just a question; so, we are going to do just that.
Given that:
The population Mean
= 3.15
The population variance
= 0.55
The sample size n = 50
We can calculate the Standard deviation of the sample mean
by using the formula:
![\sigma _x = (\sigma)/(√(n))](https://img.qammunity.org/2021/formulas/mathematics/college/esycuylgj0tlkpv322qccb8uk7t6ruhuf3.png)
Recall that:
The population variance
= 0.55
So;
![\sigma= √(0.55)](https://img.qammunity.org/2021/formulas/mathematics/college/9sjzkektq2bjnd56drw95bg1vqvy9ljakk.png)
![\sigma=0.7416](https://img.qammunity.org/2021/formulas/mathematics/college/j3h49zlwfk7mqo3p0vyxocm3jqflogl7im.png)
Then:
![\sigma _x = (0.7416)/(√(50))](https://img.qammunity.org/2021/formulas/mathematics/college/wmggnmz544hj96j4u9co9h0o8rizjp637n.png)
![\mathbf{\sigma _x =0.1049}](https://img.qammunity.org/2021/formulas/mathematics/college/aey5a9se39e8p8rjxwh13rmpjilgkhf0wl.png)