Question

A trebuchet launches a pumpkin at an angle of 27 degrees at an initial velocity of 32 m/ s from the ground. What is the apogee of the pumpkin?​

Answer 1

10.77 m

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 32 m/s

Angle of projection (θ) = 27°

Acceleration due to gravity (g) = 9.8 m/s²

Apogee i.e maximum height (H) =?

Thus, the apogee i.e the maximum height of the pumpkin can be obtained as follow:

H = u² Sine² θ /2g

H = 32² × (Sine 27)² / 2 × 9.8

H = 1024 × (0.454)² / 19.6

H = (1024 × 0.206116) / 19.6

H = 10.77 m

Thus, the apogee i.e the maximum height of the pumpkin is 10.77 m.