Rewrite the function f(x)=2(x-3)^2 – 7 in the form f(x)=ax²+bx+c.

asked Mar 5, 2021 229k views

5 votes

by Fran

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3 votes

Answer:

f(x)=2x^2-12x+11

Explanation:

f(x)=2(x-3)^2-7

=2(x-3)(x-3)-7

=2(x^2-6x+9)-7

=2x^2-12x+18-7

=2x^2-12x+11

Adanilev answered Mar 10, 2021

4.9k points

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