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In a hydraulic press, a force of 20N is applied to a piston of area 2 meters square. If the area of the other piston is 4 meters square, calculate the force exerted on it

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Pressure \: of \: piston(1) = Pressure \: of \: piston(2) \\


(f(1))/(a(1)) = (f(2))/(a(2)) \\


(20)/(2) = (f(2))/(4) \\


10 = (f(2))/(4) \\

Multiply sides by 4


4 * 10 = 4 * (f(2))/(4) \\


40 = f(2)


f(2) = 40 \: \: N

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