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What volume of O2 would be required to react with 4.6 grams of Na

User Francky
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1 Answer

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Volume of O₂ = 1.12 L

Further explanation

The reaction equation is the chemical formula of reagents and product substances

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products

Reaction

4Na+O₂ ⇒ 2Na₂O

Ar Na = 23 g/mol

  • mol Na :


\tt mol=(4.6)/(23)=0.2

  • mol O₂ :


\tt (1)/(4)* 0.2=0.05

Assume at STP (0 C, 1 atm), 22.4 L for 1 mol , then volume of O₂ :


\tt 0.05* 22.4=1.12~L

User Adriano Silva
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