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A 350.0 mL sample of gas has a temperature of 22.7 C and a pressure of 0.914 atm. What temperature would be needed for the same amount of gas to fit into a 220.0 mL flask at standard pressure?

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User Tesfa
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1 Answer

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Answer:

T₂ = 203.4 K

Step-by-step explanation:

Given data:

Initial volume = 350.0 mL

Initial temperature = 22.7 °C

Initial pressure = 0.914 atm

Final temperature = ?

Final volume = 220.0 mL

Final pressure = standard = 1 atm

Solution:

First of all we will convert the temperature into kelvin.

22.7 °C + 273 = 295.7 K

Formula:

P₁V₁/T₁ = P₂V₂/T₂

T₂ = P₂V₂T₁ /P₁V₁

T₂ = 1 atm × 220.0 mL × 295.7 K / 0.914 atm × 350.0 mL

T₂ = 65054 atm.mL.k /319.9 atm.mL

T₂ = 203.4 K

User Manish Nautiyal
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