Assuming the block is pulled with constant speed, there is no net force acting on it, so that
n + (-w) = 0
p + (-f ) = 0
where n and w denote the magnitudes of the normal force and the block's weight (both acting in the vertical direction), and p and f denote the magnitudes of the pulling and friction forces (both in the horizontal direction).
f is proportional to n by a factor µ = 0.60, so that
f = 0.60 n
The block has weight
w = (1.5 kg) (9.80 m/s²) = 14.7 N
and hence n = 14.7 N.
Then the friction force has magnitude
f = 0.60 (14.7 N) ≈ 8.8 N
and opposes the direction of movement.