Question

Find the first four terms of the sequence:

an= 54+ 3(n-1) n= 1, 2, 3...

Answer 1

`\bold{Hello!}\\\bold{Your~Answer~Is~Below!}`

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`\bold{Solution~Steps:}`

`1.)~54+3(1-1):`

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  `\bold{Subtract~1~from~1~to~get~0.}`

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  `\bold{Multiply~3~and~0~to~get~0.}`

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  `\bold{Add~54~and~0~to~get~54.}`

`2.)~54+3(2-1):`

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  `\bold{Subtract~1~from~2~to~get~1.}`

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  `\bold{Multiply~3~and~1~to~get~3.}`

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  `\bold{Add~54~and~3~to~get~57.}`

`3.)~54+3(3-1):`

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  `\bold{Subtract~1~from~3~to~get~2.}`

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  `\bold{Multiply~3~and~2~to~get~6.}`

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  `\bold{Add~54~and~6~to~get~60.}`

`4.)~54+3(4-1):`

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  `\bold{Subtract~1~from~4~to~get~3.}`

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  `\bold{Multiply~3~and~3~to~get~9.}`

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  `\bold{Add~54~and~9~to~get~63.}`

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`\bold{Answers:}`

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  `\bold{Term~1=\boxed{54}}`

• 
  `\bold{Term~2=\boxed{57}}`

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  `\bold{Term~3=\boxed{60}}`

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  `\bold{Term~4=\boxed{63}}`

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`\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~~~~~-TotallyNotTrillex}`