Question

PLEASE CHECK MY WORK!

Answer 1

This function is defined! Look at 1st and 2nd portions. It is clearly defined at both f(0) and f(2)!

Check the correct answer by putting:

`f(0)=(x+2)^2 -1=(0+2)^2-1=4-1=3`

and:

`f(2)=-2+1=-1`

Therefore:
`f(0)>f(2)`. (Option 2)