Question

Can anyone please help me with number 2 ❤️

Answer 1

`A = 101.5825591635`°

Explanation:

We can use the law of cosines. We have a triangle with side lengths as attached. (See image.)

So we want to solve for angle A.

We do this by using:

`cos(A)=(b^2 + c^2 - a^2) / (2bc)`

Here we have:

a = 36

b = 27

c = 19

So we plug in to get:

`cos(A)=(27^2 +19^2-36^2)/(2*27*19)`

`cos(A)=-0.20077972709`

`A = 101.5825591635`°