Question

Calculate the molarity of 500.0 mL of solution in which 50.0g of HCL has been dissolved

Answer 1

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• Given - 500 mL of solution containing 50g water

• To calculate - molarity of the solution

We know that ,

`Molarity \: (M) = (no. \: of \: moles \: of \: solute )/(volme \: of \: solution) \\`

it can be seen that we aren't provided with the no. of moles of solute in the question.

So let's calculate it using the given formula ~

`no. \: of \: moles \: of \: solute = (given \: mass)/(molar \: mass) \\ \\ \longrightarrow \: (50)/(36.5) \\ \\ \longrightarrow \: 1.37 \: moles \: ( \: approx \: )`

Also ,

we're given that volume of solution = 500 mL = 0.5 L

Substituting the values in the formula of molarity , we get

`Molarity = (1.37)/(0.5) \\ \\ \bold{\implies \: \boxed{Molarity = 2.74M}}`

hope helpful ~