Question

g Benton Industries manufactures carpets and draperies in the Atlanta area. Employee absenteeism was becoming a problem, so HR conducted a study involving a random sample of employees. The number of absences during the past year was tabulated by marital status. What is the probability that an employee is not married and has between 1 and 5 absences in the past year

Answer 1

The probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.

Explanation:

The probability of an event, say E is the ratio of the favorable number of outcomes to the total number of outcomes.

`P(E)=(n (E))/(N)`

The number of absences during the past year tabulated by marital status is as follows:

Marital Status 0 Absences 1 - 5 Absences More than 5 Absences

Married 100 98 52

Not Married 77 102 71

Compute the probability that an employee is not married and has between 1 and 5 absences in the past year as follows:

`P(\text{NM}\cap 1-5\ \text{Absences})=\frac{n(\text{NM}\cap 1-5\ \text{Absences})}{N}`

`=(102)/(100+98+52+77+102+71)\\\\=(102)/(500)\\\\=0.204`

Thus, the probability that an employee is not married and has between 1 and 5 absences in the past year is 0.204.