A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?

asked Jul 2, 2023 12.5k views

11 votes

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2 votes

Answer:

0.315C

Step-by-step explanation:

Force/Electric field

7520N/23900C

USB answered Jul 8, 2023

by USB

7.5k points

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