Question

A model rocket is launched with an initial upward velocity of 183 ft/s. The rocket's height h (in feet) after t seconds is given by the following.

h=183t-16t^2
Find all values of t for which the rocket's height is 95 feet.

Answer 1

0.55 seconds and 10.89 seconds

Explanation:

h = 183t − 16t²

95 = 183t − 16t²

16t² − 183t + 95 = 0

Solve with quadratic formula:

t = [ -(-183) ± √((-183)² − 4(16)(95)) ] / 2(16)

t = (183 ± √27409) / 32

t = (183 ± √27409) / 32

t ≈ 0.55 or 10.89