Find the root of the equasion (2y+1)^2–4y^2=5

asked Feb 8, 2021 19.6k views

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Find the root of the equasion
(2y+1)^2–4y^2=5

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Answer:

the root of the equation is y=1

Explanation:

$(2y + 1)^(2) - 4 {y}^(2) = 5 \\ 4 {y}^(2) + 2 * 2y * 1 + {1}^(2) - 4 {y}^(2) = 5 \\ 4y + 1 = 5 \\ 4y = 5 - 1 \\ 4y = 4 \\ y = 1$

Ian Turner answered Feb 12, 2021

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