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What is the ineqaulity to describe the relationsip between -1 2/3 and -1/4

User Cryptonkid
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1 Answer

3 votes

Answer:


\displaystyle -1(2)/(3) < -(1)/(4)

Or:


\displaystyle -(1)/(4) > -1(2)/(3)

Explanation:

Before comparing both fractions, let's express them as proper or improper fractions.


\displaystyle -1(2)/(3)=-(5)/(3)

That is an improper fraction whose value is less than -1

The fraction -1/4 is a proper fraction with a value greater than -1, which makes it greater than the other fraction. Thus:


\displaystyle -1(2)/(3) < -(1)/(4)

Or, equivalently:


\displaystyle -(1)/(4) > -1(2)/(3)

User Max Kanter
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