Answer:
The coordinates of the image of Δ ABC are:
A' (-2.5, -2.5), B' (10, 0), C' (5, 7.5)
Explanation:
Let us revise the rule of dilation
If the point (x, y) dilated by scale factor k centered at the origin, then the image of the point is (k x, k y)
We will use this rule to solve the question
∵ The vertices of triangle ABC are A (-1, -1), B (4, 0), C (2, 3)
∵ The scale factor of a dilation is 2.5
∴ k = 2.5
∵ The center is the origin
→ That means multiply each coordinate of the points by 2.5
∴ A' = (-1 × 2.5, -1 × 2.5)
∴ A' = (-2.5, -2.5)
∴ B' = (4 × 2.5, 0 × 2.5)
∴ B' = (10, 0)
∴ C' = (2 × 2.5, 3 × 2.5)
∴ C' = (5, 7.5)
The coordinates of the image of Δ ABC are:
A' (-2.5, -2.5), B' (10, 0), C' (5, 7.5)