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What is an equation of the line that passes through the point (8,2) and is parallel to the line x+4y=28

1 Answer

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Answer:

y = -1/4x + 4

Explanation:

x+4y=28

4y = -x + 28

y = -1/4x + 7

slope m = -1/4

Parallel lines have similar slope so we'll use -1/4 from above and given point (8,2) to find y-intercept.

y = mx +b

2 = -1/4(8) + b

2 = -2 + b

b = 4

Using m and b from above we can now form the new equation of line that is parallel to y = -1/4x + 7.

y = mx + b

y = -1/4x + 4

User Roy Bogado
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