Question

What is an equation of the line that passes through the point (8,2) and is parallel to the line x+4y=28

Answer 1

`y =(-1)/(4)x + 4`

Explanation:

Parallel lines have same slope

x + 4y = 28

4y = -x + 28

`y=(-1)/(4)x+(28)/(4)\\\\y=(-1)/(4)x+7`

m = (-1/4) and line passes through (8 , 2)

Equation: y - y₁ = m(x - x₁)

`y - 2 = (-1)/(4)(x - 8)\\\\y -2 = (-1)/(4)x - 8*(-1)/(4)\\\\y -2 = (-1)/(4)x + 2\\\\ y = (-1)/(4)x + 2 +2\\\\ y =(-1)/(4)x + 4`