Question

Make a truth table for the conditional statement
~(q + ~p)

Answer 1

9514 1404 393

Answer:

see below

Explanation:

The statement is equivalent to ~q·p (by DeMorgan's theorem).

`\begin{array}{ccc}p&q&\\eg(q+\\eg p)\\T&T&F\\T&F&T\\F&T&F\\F&F&F\end{array}`