Question

6. When 45.0 g of water is heated from 25.0 0C to 40.0 °C, how much energy was absorbed

during the process?
Help please due 11:59 tonight

Answer 1

2835J

Step-by-step explanation:

Q = mcΔT

Given,

• Q = ?
• m = 45.0 g
• c = 4.2
• ΔT = 40-25 = 15°C

Q = 45 × 4.2 × 15

Q = 2835 J