Question

In a certain family, the probability of having twins in 0.08 and the probability of having a single baby is 0.92.

What is the probability of a family having two sets of twins?

Answer 1

Answer: SE = √. pA(1 - pA). nA. +. pB(1 - pB). nB. = √. 0.08(0.92). 200. +. 0.344(0.656). 200. = 0.039. (b) The sample sizes of 200 are large enough

Explanation: