Explanation:
there are 13 out of 52 diamond cards.
and there are 26 out of 52 black cards.
so, for the first card to be diamond the probability is
13/52 = 1/4 = 0.25
but now, he does not put the card back.
he pulls the second card out of 51 possible cards.
the desired cases are still 26.
so, the probability to pull a black card as the second card under the restriction that the first card was a diamond is
26/51 = 0.509803922...
the probability for that combined event is then
1/4 × 26/51 = 26/204 = 13/102 = 0.12745098...
so, c. is the right answer.