Question

A car drives horizontally off a cliff at a speed of 35 m/s. the cliff is 100-m tall. how far will the car go before it hits the ground?

ADD EXPLANATION PLEASE

Answer 1

x = 157.85 m

Step-by-step explanation:

Given that,

Speed of car in horizontal direction, v = 35 m/s

Height of the cliff is 100 m

Let t is the time taken by the car to hit the ground. It can be calculated using second equation of motion which is :

`s=ut+(1)/(2)at^2`

Here, u = 0 and a = g

`s=(1)/(2)gt^2\\\\t=\sqrt{(2s)/(g)} \\\\t=\sqrt{(2(100))/(9.8)} \\\\t=4.51\ s`

Let x is the distance. So,

`x=vt\\\\x=35\ m/s* 4.51\ s\\\\x=157.85\ m`

So, it will cover a distance of 157.85 m.