Answer:
the 8th term = 111
Explanation:
39-27=12
51-39=12
63-51=12
It’s clear that ,in this sequence we add 12 each time to a term to get the next term.
This means that this is an arithmetic sequence with a common difference of 12.
Therefore,
Term1 = 27 ; Term2 = 39 ; Term3 = 51 ; Term4 = 63
Term5 = 75
Term6 = 87
Term7 = 99
Term8 = 111
Method 2 :
Un = U1 + (n-1)r
r is the common difference = 12
U1 = 27 is the first term
Then
U8 = 27 + (8-1)×12
= 27 + 7×12
= 27 + 84
= 111