A car accelerates from rest at 4.5 m/s² for 3 seconds, the car's velocity after 3 seconds is 13. 5 m/s
The distance the car travel in the 3 seconds is 40. 5m/s
The first equation of motion is v = u + a t. It explains the relationship between velocity and time.
V = Final velocity
u = Initial velocity
a = acceleration
t = time.
How to determine the velocity
When an object is brought to rest or moves from resting, U, initially velocity equals 0.
From the formula,
V = u + at
V = ?
u = 0, because the object was at rest.
a = 4. 5 m/ s²
t = 3 seconds
Velocity, V = 0 + 4. 5 × 3
Velocity , V = 0 + 13. 5
Velocity, V = 13.5 m/s²
How to determine the distance
Velocity = Distance ÷ time
Velocity, V = 13. 5 m/s²
time = 3 seconds
distance = ?
Distance = Velocity × time
Distance = 13. 5 × 3
Distance = 40. 5 m
Therefore, the car's velocity after 3 seconds is 13. 5 m/s² and the distance the car travels after 3 seconds is 40. 5m