Answer:(approx) 6.
Step-by-step explanation:Here μ=51 and σ=15
Z=
σ
X−μ
=
15
X−151
When X=120, Z=
15
120−151
=−2.067
When X=155, Z=
15
155−151
=0.2667
When X=185, Z=
15
185−151
=
15
35
=2.2667
(i) P(120<X<155)=P(−2.07<Z<0.27)
=∫
−2.067
0.2667
ϕ(z)dz=∫
0
0.2667
ϕ(z)dz+∫
0
2.0667
ϕ(z)dz
=0.4803+0.1026=0.5829.
Here N=500
∴ The number of students whose weight is between 120 and 155 pounds is
0.5872×500=291
(ii) P(X<185)=P(Z>2.27)=∫
2.2667
∞
ϕ(z)dz
=∫
0
∞
ϕ(z)dz−∫
0
2.2667
ϕ(z)dz=0.5−0.4881=0.0119
∴ the number of students with weight about 185 pounds.
=0.0119×500= (approx) 6.