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Given the isotopic symbol below- how many neutrons are present in this

beryllium ion? Answer with just a number*
1 point
9
+2
Be
4.

Given the isotopic symbol below- how many neutrons are present in this beryllium ion-example-1
User Eimear
by
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1 Answer

2 votes

Answer:

5 neutrons.

Step-by-step explanation:

The following data were obtained from the question:

Mass number = 9

Atomic number = 4

Charge = +2

Neutron number =.?

Next, we shall determine the number of protons in the beryllium ion. This can be obtained as follow:

The atomic number is simply the number protons present in the atom. Thus,

Proton = Atomic number

Atomic number = 4

Proton = Atomic number = 4

Finally, we shall determine the Neutron number as follow:

Mass number = 9

Proton number = 4

Neutron number =.?

Mass number = Proton + Neutron

9 = 4 + Neutron

Collect like terms

Neutron = 9 – 4

Neutron = 5

Thus, there are 5 neutrons b present in the beryllium ion.

User Qiuxiafei
by
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