Question

The specific heat capacity of water is 4.18 J/(g•°C). When 200 grams of water cools from 50.°C to 25°C, the total amount of heat energy released by the water is

Answer 1

The total amount of heat energy released by the water is 20,900 J

Step-by-step explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The sensible heat of a body is the amount of heat received or transferred by a body when it undergoes a temperature variation without there being a change in physical state (solid, liquid or gaseous). Its mathematical expression is:

Q = c * m * ΔT

Where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the variation in temperature.

In this case:

• Q=?
• c= 4.18
  `(J)/(g*C)`
• m= 200 g
• ΔT= Tfinal - Tinitial= 50°C - 25°C= 25°C

Replacing:

Q= 4.18
`(J)/(g*C)` *200 g* 25°C

Solving:

Q=20,900 J

The total amount of heat energy released by the water is 20,900 J