Answer:
m∠A = 102°
Explanation:
In quadrilateral ABCD, BC is perpendicular to CD
m∠BCD = 90°
(7x - 36) = 90°
7x = 90 + 36
7x = 126
x = 18
Since, m∠A = (5x + 12)
Therefore, m∠A = (5×18) + 12
= 90 + 12
= 102°
Measure of angle A = 102°
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