Question

A block with a mass of 34.0 kg is pushed with a horizontal force of 150 N. The block moves at a constant speed across a level, rough surface a distance of 6.95 m. (a) What is the work done (in J) by the 150 N force

Answer 1

Complete Question

A block with a mass of 34.0 kg is pushed with a horizontal force of 150 N. The block moves at a constant speed across a level, rough surface a distance of 6.95 m.

(a) What is the work done (in J) by the 150 N force

b) find the coefficient of kinetic friction between the crate and rough surface

Answer:

a

`W =  1042.5 \ J`

b

`\mu_k =  0.45`

Step-by-step explanation:

From the question we are told that

The mass of the block is
`m =  34.0 \  kg`

The horizontal force is
`F =  150 \ N`

The distance moved is
`d = 6.95 \  m`

Generally the work done is mathematically represented as

`W =  F  *  d`

=>
`W =  150  * 6.95`

=>
`W =  1042.5 \ J`

Generally the net force acting on the block is

`F_(net) =  F -  m  *  g *  \mu_k`

=> Here
`F_(net)  =  m *  a`

Here a is the acceleration and the value is zero because velocity is constant

So

`F_(net)  =  34.0  *  0`

So

`\mu_k =  0.45`