Question

The perimeter of a rectangle is 50 yards. The width is 1 more than one-half of the length. What are the dimensions of the rectangle?

Answer 1

The length of the rectangle is 16 yards

The width of the rectangle is 9 yards

Explanation:

The given parameters are;

The perimeter of the rectangle = 50 yards

The width, W of the rectangle = 1 + Length, L/2

Therefore we have;

W = 1 + L/2

2 × W + 2 × L = 50

2 × (1 + L/2) + 2 × L = 50

2 + L + 2·L = 50

3·L = 50 - 2 = 48

L = 48/3 = 16

The length, L = 16 yards

The width, W = 1 + L/2 = 1 + 16/2 = 1 + 8 = 9

The width, W = 9 yards.