Question

A magnetic field of magnitude 0.360 T is oriented perpendicular to the plane of a circular loop. HINT (a) Calculate the loop radius (in m) if the magnetic flux through the loop is 2.65 Wb. m (b) Calculate the new magnetic flux (in Wb) if the loop radius is doubled.

Answer 1

(a) the loop radius (in m) = 1.531 m

(b) the new magnetic flux, when the loop radius is doubled = 10.61 Wb

Step-by-step explanation:

Given;

magnitude of magnetic field, B = 0.36 T

magnetic flux, Ф = 2.65 Wb

(a) the loop radius (in m)

magnetic flux is given by;

Ф = BA

Where;

A is the circular area of the loop

A = πr²

Ф = B.πr²

`r = \sqrt{(\phi)/(B\pi) }\\\\ r = \sqrt{(2.65)/(0.36\pi) }\\\\r = 1.531 \ m`

(b) the new magnetic flux, when the loop radius is doubled

Ф = B.πr²

Ф = 0.36 x π x (2 x 1.531)²

Ф = 10.61 Wb