Question

PLEASe help math ...

Answer 1

Area of the trapezium

• 1/2(Sum of parallel sides)×Height
• 1/2(2+8)(4)
• 2(10)
• 20units²

Area of semicircle

• π(2/2)²/2
• π/2
• 1.57units²

Total area

• 20+1.57
• 21.6units²(Rounded)

Answer 2

21.6 units² (nearest tenth)

Explanation:

`\textsf{Area of a trapezoid}=(1)/(2)(a+b)h \quad \textsf{(where a and b are the bases and h is the height)}`
`\textsf{Area of a semicircle}=\frac12 \pi r^2 \quad \textsf{(where r is the radius)}`

Given:

• a = 2
• b = 8
• h = 4
• r = 2 ÷ 2 = 1

`\begin{aligned}\textsf{Area of figure} & =\textsf{area of trapezoid + area of semicircle}\\& = (1)/(2)(a+b)h+(1)/(2) \pi r^2\\& = (1)/(2)(2+8)(4)+(1)/(2) \pi (1)^2\\& = 20+(1)/(2) \pi\\& = 21.6\: \sf units^2 \:(nearest\:tenth)\end{aligned}`