Question

With one method of a procedure called acceptance sampling, a sample of items is randomly selected without replacement and the entire batch is accepted if every item in the sample is okay. The ABCD Electronics Company has just manufactured 7000 write-rewrite CDs, and 180 are defective. If 5 of these CDs are randomly selected for testing, what is the probability that the entire batch will be accepted? Report the answer as a percent rounded to one decimal place accuracy. You need not enter the "%" symbol. prob = %

Answer 1

Probability of non Defective Cds =85.28 %

Explanation:

The total number of Cds = 7000

No of defective Cds = 180

Probability of non Defective Cds =

(7000-180)/7000 *(7000-181)/6999* (7000-182)/6998 * (7000-183)/6997 * (7000-184)/6996

= 6820/7000* 6819/6999* 6818/6998 * 6817/6997 * 6816/6996

= 0.9742 *0.9742 *0.9742 *0.9742 *0.9742

= 0.8528

The probability that the entire batch will be accepted is 0.8528 or 85.28%

85.28 % means out of 100 more than 85 will be accepted.

The percent means out of hundred . When we divide 85.28 by 100 we get 0.8528 which is probbaility obtained.

So it can be written both ways.