As OP bisects ∠AOR, ∠AOP = ∠POR = 55°
So, ∠AOR = ∠AOP + ∠POR = 55° + 55° = 110°
As OS bisects ∠ROB, ∠ROS = ∠SOB = x
As total angle on a line is 180°,
110° + x + x = 180°
=> 2x = 70
=> x = 35°
∠POS = ∠POR + ∠ROS = 55° + x = 55° + 35°
=> ∠POS = 90°
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